Metadata-Version: 2.1
Name: compare_string_version
Version: 0.1.0
Summary: accepts 2 version string as input and returns whether one is greater than, equal, or less than the other
Home-page: https://github.com/miguelluiz/compare_string_version
Author: Miguel Almeida
Author-email: mplabdev@gmail.com
License: MIT
Download-URL: https://github.com/miguelluiz/compare_string_version/archive/v_01.tar.gz
Description: This is a software library that accepts 2 version string as input and 
        returns whether one is greater than, equal, or less than the other. 
        As an example: "1.2" is greater than "1.1". 
        
        REQUIREMENTS: PYTHON 3. and above
        
        usage:
        
            from compare_string_version import compareVersion
            print(compareVersion(a,b))
            
        expected return
        
        when
        
            a==b:
        
                a is equal to b
        
            a>b:
        
                a is greater than b
        
            a<b: 
        
                a is less than b
        
        Exceptions:
        
        either a is null and/or b is null:
            Value(s) can not be null: Both values must be string    
        either a and/or b are/is not a string:
            Both must be string
        
        assumptions:
        
            a and b are string
            
            a and b are not null (None)
            
            both version strings only contain numbers (0...9) and this char '.':
        
                123.456.789.012
        
                'A..Z','a..z' and any other chars like "! @ # $ % * [ } ] { ^ Ã§ ? ; : . > , < | " will be removed from the comparison:
                    some adjustment would be applied after char removal:
                    '..' will be replaced by '.'
                    string ending in '.' will be shorted by 1
        
            this '..' will not be accepted as it is '.' duplicated:
                    '10..12..13..14' will become '10.12.13.14'
        
            the comparison would be from the group split by the char '.':
                    10.12.13.14 would be treated as 10 12 13 14
                    01.10.100.001 would be treated as 1 10 100 1
        
            all the comparison would check the integer part of the version:
                    '10.0' is equal to '010.0.0.0.0.0.0.0' because int('10.0') is equal to int ('010')
        
            whoever version number has the higher far left group would be named as greater:
                    10.0.0.0.0.1 is greater then 9.9.9.9.9.9.9
                    0.1.0.0.0.0.1 is greater than 0.0.9
                    the same "int" rule will be applied for any other group in the string
        
            all '0's from the left will be disregarded if its value is '0':
                    1.0.0.0 is equal to 1.0 and it is equal to 1
                    
                    
        the following .py were used in order to test data
        
        test997.py has generated output5.txt
        
        test996.py has generated output4.txt
        
        test995.py has generated output1.txt and output2.txt
        
        test994.py has generated output3.txt
Keywords: Compare,version control,version string as input
Platform: UNKNOWN
Classifier: Development Status :: 3 - Alpha
Classifier: Intended Audience :: Developers
Classifier: Topic :: Software Development :: Build Tools
Classifier: Topic :: Software Development :: Internationalization
Classifier: Operating System :: OS Independent
Classifier: License :: OSI Approved :: MIT License
Classifier: Programming Language :: Python :: 3
Classifier: Programming Language :: Python :: 3.4
Classifier: Programming Language :: Python :: 3.5
Classifier: Programming Language :: Python :: 3.6
Classifier: Programming Language :: Python :: 3.7
Description-Content-Type: text/markdown
