Metadata-Version: 2.1
Name: rect-intersection
Version: 0.10
Summary: Checks if two rectangles intersect
Home-page: https://github.com/hansalemaos/rect_intersection
Author: Johannes Fischer
Author-email: <aulasparticularesdealemaosp@gmail.com>
License: MIT
Keywords: rectangles,intersect
Classifier: Development Status :: 4 - Beta
Classifier: Programming Language :: Python :: 3 :: Only
Classifier: Programming Language :: Python :: 3.9
Classifier: Topic :: Scientific/Engineering :: Visualization
Classifier: Topic :: Software Development :: Libraries :: Python Modules
Classifier: Topic :: Text Editors :: Text Processing
Classifier: Topic :: Text Processing :: General
Classifier: Topic :: Text Processing :: Indexing
Classifier: Topic :: Text Processing :: Filters
Classifier: Topic :: Utilities
Description-Content-Type: text/markdown
License-File: LICENSE.rst


# Checks if two rectangles intersect 


```python
# Tested with:
# Python 3.9.13
# Windows 10

from rect_intersection import intersects

# Allowed formats for box1/box2 
format_1x4 = (0, 0, 100, 200)
format_4x2 = [(0, 0), (100, 0), (100, 200), (0, 200)]
format_2x2 = [(0, 0), (100, 200)]

box1 = (0, 0, 100, 200)


box2 = (1000, 1000, 2000, 2000)
print(intersects(box1, box2))
box2 = (50, 20, 2000, 2000)
print(intersects(box1, box2))
box2 = [(50, 20), (2000, 20), (2000, 2000), (50, 2000)]
print(intersects(box1, box2))
box2 = [(50, 20), (2000, 2000)]
print(intersects(box1, box2))


box2 = (1000, 1000, 2000, 2000)
print(intersects(box1, box2))
box2 = (50, 20, 2000, 2000)
print(intersects(box1, box2))
box2 = [(50, 20), (2000, 20), (2000, 2000), (50, 2000)]
print(intersects(box1, box2))
box2 = [(50, 20), (2000, 2000)]
print(intersects(box1, box2))

box2 = (1000, 1000, 2000, 2000)
print(intersects(box1, box2))
box2 = (50, 20, 2000, 2000)
print(intersects(box1, box2))
box2 = [(50, 20), (2000, 20), (2000, 2000), (50, 2000)]
print(intersects(box1, box2))
box2 = [(50, 20), (2000, 2000)]
print(intersects(box1, box2))



False
True
True
True
False
True
True
True
False
True
True
True

	
```




